Nevada, OH


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Nevada (pronounced nah-VAY-da) is a village in Wyandot County, Ohio, United States. The population was 814 at the 2000 census.
Nevada is located at 40°49′1″N 83°7′54″W / 40.81694°N 83.13167°W / 40.81694; -83.13167 (40.816867, -83.131664).
According to the United States Census Bureau, the village has a total area of 1.0 square miles (2.7 km²), all of it land.