Horseshoe Bend, AR
Horseshoe Bend is a city in Fulton, Izard, and Sharp counties in the U.S. state of Arkansas. The population was 2,278 at the 2000 census.
Horseshoe Bend is located at 36°13′28″N 91°44′40″W / 36.22444°N 91.74444°W / 36.22444; -91.74444 (36.224390, -91.744502).
According to the United States Census Bureau, the city has a total area of 14.6 square miles (37.8 km²), of which 13.4 square miles (34.6 km²) is land, and 1.2 square miles (3.2 km²) (8.50%) is water.