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Elliott is a city in Montgomery County, Iowa, United States, along the East Nishnabotna River. The population was 402 at the 2000 census.
Elliott is located at 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°W / 41.14889; -95.16194 (41.149002, -95.162071).
According to the United States Census Bureau, the city has a total area of 0.4 square miles (1.1 km²), all of it land.